Do we have magnetic and electric field in the metal plates of a capcitor?

Question

Do we have magnetic and electric field in the metal plates of a capcitor?

Answer 1

There is no electric field inside a conductor.  The electric field between the plates is proportional to the voltage.  Or to put it differently, the voltage is a measure of the electric field.  Any magnetic fields result from moving charges (electrons) and changing electric fields.  You can calculate the details using Maxwell's equations.

Answer 2

It depends on what metal the plates are made of. Static buildup creates an electric field, but a magnetic field would have to be created by natural magnetism in the metal. Its also possible to send current through it, in which case a magnetic field would also be present.

Answer 3

There is an electric field mostly *between* the plates and a magnetic field between the plates and around the leads during discharge, especially if it is fast.

Answer 4

Yes, but the electric fields are by far the more important.

Answer 5

Assuming conducting metal plates like copper for example.

Once the capacitor is fully charged, there is "no" potential

gradient "electric field" inside the metal--->for practical purposes!.

The electric field extends from the surface of one plate to the

surface of the other. The electric&magnetic fields exist together

only during the charging process--> for practical purposes!.

The post above is correct: koggit

Answer 6

Once the plates of the capacitor are fully charged (which, in reality, never happens -- but theoretically it happens as t approaches infinity) there is no electric field in the plates, by the Charged Isolated Conductor Theorem.  Before the plates are fully charged (t<infinity) there is a current in the plates (charging them) which creates a magnetic field.

So, the answer so your question varies with time.

t=infinity: no electric nor magnetic field

t<infinity: both an electric & magnetic field

At all t>0, there is an electric field between the two plates (caused by the potential difference).