Do you guys know how to find the x and y intercept of x^-2x-15. (^)=squared I need help please!!!?

Question

i've been stuck on this help please.!!

Answer 1

Oh, your equation is x^2-2x-15?

then y=(x-5)(x+3)

when x=0, y=-15, so y=-15 is your y intercept

there are two x intercepts at x=5 and x=-3

at those points y=0

Answer 2

(x-5)(x+3) = 0

The x intercepts are: (5, 0) (-3, 0)

x^2 - 2x - 15



The y intercept is (0, -15)



I think this is right..