Question:

Does Anyone knows how to solve this math prob? 10-[6 – 2 • 2 + (8 - 3)]?

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Evaluating expressions

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  1. 10-[6-2x2+(8-3)]

    10-[6-2x2+(5)]

    10-[6-4+5]

    10-7= 3

    3


  2. 3

  3. Use the order of operation (parenthesis, exponents, multiplication/division,  addition/subtraction)  Easily remembered by: Please excuse my dear aunt sally   Do the inner parenthesis first, then within the outer parenthesis do the multiplication first then the subtraction and addition from left to right, then do the math outside of the parenthesis.  In other words first 8-3=5 then 2x2=4 then 6-4=2 then 2+5=7  then 10-7=3

  4. yep yep 3

  5. 10 - (6 - 4 + 5) =

    10 - 7 = 3.

  6. 10-[6 – 2 • 2 + (8 - 3)]

    10-[6-2*2 +(5)]

    10-[6-4+5]

    10-(2+5)

    10-7

    3

  7. 10-[6-2x2+(8-3)]

    10-[6-4+(5)]

    10-[2+(5)]

    10-7

    3

  8. First you must work inside the parenthesis and complete everything inside the brackets before working with the ten on the outside.  

    10-[6-2X2+(8-3)]

    10-[6-2x2+(5)]

    10-[6-4+(5)]

    10-[2+(5)]

    10-[7]

    10-7=3


  9. 10 - [6-4+5]

    10-7=3

    Brackets mean the same thing as parenthesis.

  10. Here are the steps:

    1. 10-[6-2 x 2+ (8-3)]        write out the original equation

    2. 10-[6-2 x 2 +5]            evaluate what's inside the parentheses

    3. 10-[6-4+5]                   multiply 2 by 2

    4. 10-[7]                         combine all like terms

    5.  3                              subtract 7 from 10 to get the solution of 3

    Hope this helps! If you have any other questions, please feel free to ask.  

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