Question:

Does the function 1/(√x-4) have an inverse? if so, how do you know?

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It's just a math question

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  1. y = 1/(√x-4)

    let us first find the inverse

    interchange y by x and x by y

    x= 1/(√y-4)

    solve for y

    x^2 = 1 / (y-4)

    y-4 = 1/ x^2

    y = 1/ x^2  +4

    so,

    f^-1(x) = 1/x^2 + 4

    get the graph of this function.

    you will find that it fails the horizontal line test.

    so this inverse is not a function.

    or

    the function 1/(√x-4) has no inverse


  2. y = 1/[sqrt(x) - 4]

    Inverse means x = 1/[sqrt(y) - 4] then solve for y.

    1/x = sqrt(y) - 4

    1/x + 4 = sqrt(y)

    (1/x + 4)^2 = y

  3. A function has an inverse if the function is one-to-one (i.e. if f(a) = f(b) then a = b).

    I'm assuming you mean:

    f(x) = 1/√(x - 4)

    This function is one to one.  Therefore, it will have an inverse.

    Hope this helps!

  4. yes.  it is (sqrt(x) - 4).  remember that x can not equal 16 because that would be 1/0 which is an irrational number.  x also can not be less than zero as that would be an imaginary number.  inverses are easy.  just multiply by 1 / the function.  there is a button for it on a scientific calculator labelled either 1/x or x^-1.

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