Does this look right? In a series RLC circuit, at frequencies above the resonant frequency, the circuit become

Question

In a series RLC circuit, at frequencies above the resonant frequency, the circuit becomes INDUCTIVE REACTANT.

Answer 1

In a series RLC circuit, at frequencies above the resonant frequency, the circuit become  .. capacitive

Answer 2

Yes, the answer above about it being inductive is correct, but to explain - when we talk about a circuit being  "inductive", "resistive", or "capacitive", what we mean is, what is the dominant voltage drop due to, resistance, inductance, or capacitance.  We already know that, since R=E/I, resistance does not vary with frequency, therefore it will remain constant with frequency.  Then we look at the reactance.  Since Xc=1/2(PI)fC, capacitive reactance decreases with frequency (because the "f" term is below the denominator).  Therefore capacitive voltage drop decreases with frequency, and a capacitor gets closer to just looking like a piece of wire.  But for inductors, XL=2(pi)fL, so inductive reactance increases with frequency, therefore the voltage drop across an inductor increases with frequency.  Above resonance, the voltage drop across the inductor will become greater than that across the capacitor, and at some frequency (could be either above or below resonance) inductive reactance will become greater than resistance, and keep on increasing with frequency, making the circuit eventually dominated by inductive reactance.

BTW, resonance is just too cool.  I built a circuit a few years ago with custom low-ESR caps and litz wire coil.  Series resistance was only a small fraction of an ohm at resonance, which was about 100kHz.  I drove it with 0.033ohm MOSFET half-bridge.  With about a 3V squarewave input, we got up to aound 1kV sinewaves across the reactors, with dozens of amps circulating even tho the supply current was less than 0.1A.  thus the coil, a pancake-type, created a pretty large magnetic field, which was used to remotely (from a distance of up to about a foot away) recharge a tiny battery-powered device intended for implantation in humans.  Very cool stuff.  I have a patent for a method of tuning such a thing, #7,190,153, "System, circuit and method for tuning a resonant circuit"

Answer 3

At frequency above the resonant, any inductive element will have higher reactance compared to capacitive element.

This is so due to the fact that inductive reactance is proportional to frequency, but the reverse for capacitive reactance which become lower in reactance value.

Thus the RLC circuit will become inductive at frequency higher than resonant frequency.