EASY math problem 10 pts?

Question

How to solve ..

Marks math test scores so far are as follows: 96, 77, 87, 82. What score must Angela make on the final test in order to have a test average of 88?

the answer is 98 but how do I solve the problem?

Answer 1

First, be clear on whose test scores you're dealing with. Second, given four test scores plus an extra score that is unknown, they are all divided by 5 to get 88. Now take that 5 and multiply by 88 and let it equal to the sum of the four scores plus one mystery score. Finally, solve for the mystery score which is 98.

Answer 2

First, I assume that Mark and Angela are the same person. lol. The equation to find the average is:

(96+77+87+82+x)/5 = 88

multiply both sides by 5 to get rid of the division, giving you:

96+77+87+82+x=440

add the numbers on the left, giving you:

342+x=440

subtract 342 from both sides, leaving you with:

x=98

=-)

Answer 3

x=angela's score

88=(96+77+87+82+x)/5 ==>

5*88-96-77-87-82 =x

x=98

Answer 4

I'm not 100% sure but u do 96+77+87+82+98 then you divide that by 5 as there is 5 values so that divided by 5 makes 88

Answer 5

a final test would make the sum of tests a total of 5

5 times the average of 88 = 440

440 - (96+77+87+82) = 98

Answer 6

(96 + 77 + 87 + 82 + x) / 5 = 88

Then solve for x.

(342 + x) / 5 = 88

342 + x = 88 x 5

342 + x = 440

x = 440 - 342

x = 98

Hope that helps!

Answer 7

88 x 5 = 440             88 test average times number of tests

96 + 77 + 87 +82 = 342       total of 4 tests

440 - 342 = 98           total of 4 test subtracted from 440

                                number needed to maintain 88 average

Answer 8

I am assuming that you meant to use the same name throughout the problem

Let s be the unknown score, then

(96 + 77 + 87 + 82 + s)/5 = 88

Multiplying both sides by 5 and adding the numbers on the left

342 + s = 88*5 = 440

Subtract 342 from both sides

s = 440-342 = 98