EASY math question. Help? :]<33?

Question

d=c-b/a-b, then b=...

please show work.

Answer 1

d = c-b / a-b

d * (a-b) = c-b

da - db = c-b

-db = c-b-da

b = (c-b-da) / -d

Answer 2

if its easy then y dont u do it?!

Answer 3

if: d = (c-b)/(a-b)               Note the brackets

then: ad - bd = c - b (Multiply both sides by (a-b))

b - bd = c - ad (Add b to both sides; subtract ad from both sides)

b(1 - d) = c - ad (factor out b)

b = (c - ad)/(1 - d)

if d = c - b/a - b

then b + b/a = c - d (Move b, b/a, d)

b(1 + 1/a) = c - d (factor)

b = (c - d)/(1 + 1/a)

Answer 4

d=c-b/a-b

You&#039;re solving for b, so you want b all by itself on the left side.

Start by multiplying both sides of the equation by (a-b).  That gets rid of the fraction.

d*(a-b)=(c-b)

Distribute the d to both terms in parenthesis:

ad - bd = c-b

You want b on the left.  Add b to both sides:

b+ad-bc=c

You want b all alone on the left.  Subtract ad from both sides:

b - bc = c - ad

Factor b out of each term on the left so you can get b by itself:

b* (1 - c) = c - ad

Divide both sides by (1-c)

b = (c - ad) / (1 - c)

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