Easy problem!!! help I got half but can't get the other...?

Question

Simplify

(2x^2 - 5x - 1)(x^2 + x - 3)

Answer 1

2x^4 - 3x^3 - 11x^2 + 14x + 4

Answer 2

(2x² - 5x - 1)(x² + x - 3)

factor each

x² + x - 3

quadratic equation:

to solve ax + by + c = 0

x = [-b ±√(b²-4ac)] / 2a

x = [-1 ±√(1+12)] / 2

x = [-1 ±√(13)] / 2

x = - 1/2 + √13/2 or

      - 1/2 - √13/2

x² + x - 3 = (x + 1/2 + √13/2)(x + 1/2 - √13/2)

2x² - 5x - 1

x = [5 ±√(25+4*2)] / 4

x = [5 ±√(32)] / 4

x = [5 ±4√2] / 4

x = 5/4 + √2, 5/4 - √2

2x² - 5x - 1 = (x - 5/4 - √2)(x - 5/4 + √2)

putting them back together

(2x² - 5x - 1)(x² + x - 3)

(x + 1/2 + √13/2)(x + 1/2 - √13/2) (x - 5/4 - √2)(x - 5/4 + √2)

if I didn't make an arith mistake

.

Answer 3

(2x^2 - 5x - 1)(x^2 + x - 3)

= 2x^4 + 2x^3 - 6x^2 - 5x^3 - 5x^2 + 15x - x^2 - x + 3

= 2x^4 - 3x^3 -12x^2 +15x + 3