Electrochem: I keep getting this wrong..

Question

A metal undergoes electrolytic reduction according to ne- Mn ===> M. What current (in Ampères) must be provided to deposit the metal at a rate of 1.814 mol/hr if n = 1?

Answer 1

a rate of 1.814 mol/hr where n = 1,  needs 1.814 moles of electrons per hour

let's find out how many Coulombs that is:

1.814 mol electrons  @ 96,485 Coulombs per mole of electrons = 175,024 coulombs

Since 1 Coulomb is an amp-second, that turns into 175,024 amp-seconds

At 3600 second in an hour, how many amps is that per hour:

175,024 amp-seconds / (3600 seconds/ hour) = 48.618 amps

your answer is 48.62 amps