Engineering, calculate the reactions and loadings?

Question

I have a beam 6.5m long in from the left reaction 1m is a loading of 50kN still working from the left 2.75m in from that loading i have a loading of 30kN from here it is 2.25m to the right reaction then there is 0.5m right from this with a 7kN load at the and of the 6.5m

So from the RL to RR is 6m then right from the RR is 0.5m with a 7kN loading on it

My answers are RL = 27kN

RR = 53kN

Is this correct?

Answer 1

No.

You have a total load of 50+30+7 = 87kN whilst you have found a total reaction of only 27+53= 80kN.

Try taking moments about the Left Hand Support. Loads times distance are clockwise whilst Reaction (R) times distance to LH support (6m) is anticlockwise. Moments must balance and Reaction (L) is total load minus Reaction (R)

Answer 2

No, it is not correct.

You have 3 loads that total 87  i.e. (50+30+7)=87

If the loads total 87 then the reactions will total 87.

Summing the moments about the left reaction you get:

(1)(50)+(3.75)(30)-(6)(RR)+(6.5)(7)=0

                                                     208=(6)(RR)

                                                  34.67=RR

Therefore RL = 87 - 34.67

                 RL = 52.33