Equation for a perpendicular line that passes through the origin?

Question

line m is perpendicular to y=4x-1 and passes through the origin whats the equation for line m?

plz some tell me how to solve this thing

Answer 1

The slope of two perpendicular lines have opposite reciprocal slopes.

So if one's 1, the other is -1.

If one's -3, the other is 1/3, etc.

Here, the slope of the given line is 4, so the slope of the reciprocal line is -1/4

The origin is the point (0, 0)

Since we have an x, y, and m. We can solve for b:

y = mx + b

0 = (-1/4)(0) + b

0 = 0 + b

b = 0

So your perpendicular line is:

y = -(1/4)x

Answer 2

Slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept

Perpendicular lines have slopes that are opposite reciprocals of each other. Line y = 4x - 1 has a slope of 4, so line m, which is perpendicular to it, will have a slope of -1/4. Thus, its equation so far is y = (-1/4)x + b. Since the line goes through the origin, which is point (0, 0), then b = 0, so the equation is:

y = (-1/4)x <===ANSWER

Answer 3

perpendicular slope is -1/4

so m=-1/4 x=0 y=0

s y=-1x/4

or better written as y=-x/4