Equation of the line? help?

Question

find an equation of the

1. line through the point (4,0) and perpendicular the line 4x+3y=2

2. Circle with center at (2b, 3b) and tangent to the y-axis

Answer 1

1.   y=(3/4)(x-4)

2.    (x-3b)^2+(y-b)^2=1

Answer 2

4x+3y=2

transform to y=mx+b

3y= -4x+2

y= -4/3x+2/3

m= -4/3

then since it is perpendicular, get the negative reciprocal of the slope

m=3/4

then use Y-Y1=m(X-X1)

*1 is a subscript

Y-0=3/4(X-4)

Y-0=3/4x-3

Y=3/4x-3

thats the equation of the line in the form y=mx+b

if its in the form ax+by=c, it will be 3x-4y=12

for number 2, use this (x-h)^2+(y-k)^2=r^2

where h and k are the centers

hope this helps