Equations on the perimeter of the following shape...?

Question

The perimeter of a rectangle is 120 cm. The length is one-and-a-half times the width. Find its width, length and area.

Answer 1

Don't know if " zgrinder" is toying with you but the area would be 24 * 36

Answer 2

P=(3/2)s+s+(3/2)s+s

P=2(3/2)s+2s

P=3s+2s

P=5s

120/5=s

24=s

width=s=24cm

length=(3/2)s=36cm

area=widthxlength=24x36=864cm^2

Answer 3

Perimeter = 120  

2L + 2W = 120 (1)

L = 1.5W

subsitute into (1)

2 (1.5W) + 2W = 120

5W = 120

W = 24cm

subsitute W=24 into (1)

2L + 2W = 120

2L + 48 = 120

2L = 72

L = 36cm

Area = L x W = 36 x  24 = 864cm^2

Answer 4

Width=24cm

Length=36

Area=864 cm^2

Answer 5

P = 2(L + W)

L = 3W/2

2(3W/2 + W) = P

3W + 2W = P

5W = P

W = P/5

L = 3P/10

A = (3P^2)/50