Equilibrium constant

Question

What is the numerical value of the equilibrium constant at 25 degrees Centigrade for the equilibrium:

N2(gas) O2(gas) <-----> 2 NO(gas)

H= 180.5 kj and S= 24.772 J/K

Answer 1

Use the relations of

Gibb&#039;s free energy (measured in kJ):

G = H - TS

and

ΔG = -RTlnK, where

R = 0.008314 JK^(-1)mol^(-1)

T = temperature in Kelvins = 298.15

You should get K = 4.68E-31

[Answer: see above]