Evaluating a limit! help?

Question

http://img204.imageshack.us/img204/9703/limitlk2.jpg

Explanation would be helpful thanks, i don't understand how x+2 = 1

Answer 1

The limit doesn't exist. You take the limit as x approaches 1 for both equations.

For the left hand limit you use the equation x^2.

So you do

limit x -> 1   [f(x)] = limit x-> 1 [x^2]

                             = 1.

For the right hand limit you do this

limit x-> 1 [ f(x)] = limit x-> 1  [ x+2]

                            

                           = 3.

Since the left hand limit and the right hand limit are not equal than the limit doesn't exist.

Sorry for any confusion.