Question:

Everything i know about Chemistry is a complete lie. ?

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Compute the mass in grams of a sample of amercium containing six atoms.

6 atoms Am x (243g/atom) = 1.46 x 10^3 g

my answer according to dimensional anaylsis should be correct!

i canceled out the atoms and grams is the only thing left over!

but my book has 2.42 x 10^-21

help? by the way this isnt a h.w. question. i actually like to learn. it sounds crazy but i do.

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4 ANSWERS


  1. The number you see on the periodic table that we always call the atomic mass of the element is in reality the mass of an Avagadro's number of atoms or 1 mole of atoms. You surely cannot imagine that a single atom of Americium can have a mass of 243grams?

    So we have 6.022*10^23 atoms will have a mass of 243.0grams. Now what is the mass of just 6 of these atoms?

    Mass of 6 atoms: = (243.0/6.022*10^23)*6

    Mass = 2.42*10^-21grams


  2. lol those are some heavy atoms you got there

    hint: moles, avogadro's number etc...

  3. The unit of the AM molecular weight is wrong ( g/atom ). Its should be g/mol. Since the statement gives us a quantity in terms of atoms, we need to convert this atoms into moles. In conversion, we need the Avogadro's constant which is 6.022 x 10^23 atoms/mol.

    6 atoms Am x ( 1 mole Am/ 6.022 x10^23 atoms Am )(243 g/mol)

    THEREFORE: we have 2.42 x 10^-21 grams of AM sample.

  4. SUCK my juicy dirtstar alex

    *****

    nerdy little 14 yr. old. born in 94 eh?

    Bow down to old jabba

    See? Even Trevor ponders your reasoning. 243 grams?

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