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Expressing the limit?

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lim n-> inf ∑ Bot(i=1) top (n) [4/3(xi*)^2+6(xi*)^5] ∆x, [0,2]

how do you work this

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  1. The limiting value is clearly the integral

    ⌠[(4/3)x² +6x^5] dx evaluated from x=0 to x=2

    and that is (4/9)x^3 + x^6 = (4/9)(8) + 64 - (0+0)

    64 + 32/9 = 608/9

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