Factor COMPLETELY: 5x4 - 65x2 +180?

Question

Factor COMPLETELY: 5x4 - 65x2 +180?

Answer 1

5x4 - 65x2 +180

5(13^4)X^2 +36

x^4-13x^2+180

Answer 2

5x4 -- 65x2 + 180

= 5(x^4 -- 13x^2 + 36)

= 5(x^2 -- 4)(x^2 -- 9)

= 5(x + 2)(x -- 2)(x + 3)(x -- 3)

Answer 3

= 5x^4 - 65x^2 + 180

= 5(x^4 - 13x^2 + 36)

= 5(x² - 4)(x² - 9)

= 5(x + 2)(x - 2)(x + 3)(x - 3)

Answer: 5(x + 2)(x - 2)(x + 3)(x - 3)

Answer 4

The answer is 70

First, do 5x4. This equals 20.

Then, do 65x2. This equals 130.

Subtract 130 from 20. This equals -110.

Lastly, add 180 to -110. This equals 20.

Answer 5

factor out 5

5(x4 - 13x2 + 36)

perfect square trinomial

5(x^2 - 9)(x^2 - 4)

difference of squares

5(x -3)(x + 3)(x -2)(x + 2)

Answer 6

5x^4-65x^2+180

5(x^4-13x^2+36)

5(x^2-9)(x^2-4)

5(x-3)(x+3)(x-2)(x+2)

Answer 7

5x4 - 65x2 +180?

5x4=20

65x2=130

20- neg130= neg.110

neg.110+pos.180=70

Answer 8

I am reading this as :-

5x^4 - 65x² + 180

5 (x^4 - 13 x² + 36)

5 ( x² - 9 ) ( x² - 4 )

5 (x - 3) (x + 3) (x - 2) (x + 2)

Answer 9

20-130+180=70

Answer 10

5x4 - 65x2 + 180

=> 5x2(x2- 13x + 36)

=> 5x2(x-9)(x-4)

Answer 11

the expression is

5[x^4-13x^2+36]

=5 [k^2-13k+36]  where k=x^2

=5 [k^2-9k-4k+36]

=5[k(k-9)-4(k-9)]

=5(k-9)(k-4)

put k=x^2

=5(x^2-9)(x^2-4)   now apply x^2-y^2=(x+y)(x-y)

=5(x+3)(x-3)(x+2)(x-2) ans