Factor completely ---plz help?

Question

factor completely

100r^2 +160rp + 64p^2

Answer 1

it is easy friend (a+b)^2=a^2+b^2+2ab

dat means a=10 n b=8 n 2ab=2.10.8  

Answer 2

100r^2 +160rp + 64p^2

factor:

100r^2 = (10r) (10r)

64p^2 = (8p) (8p)

(10r + 8p) (10r + 8p) -----> ans

Answer 3

100r² + 160rp + 64p² is of the form (a + b)² = a² + 2ab + b². So, it can be written as:

(10r + 8p)².....

OR

100r² + 160rp + 64p²:

=> 4(25r² + 40rp + 16p²),

=> 4 { (5r)² + [2 × (5r) × (4p)] + (4p)² },

=> 4(5r + 4p)².... Hope that helped.....

Answer 4

(10r)^2+2x 10r x 8p +(8p)^2 [by using the formula:(a+b)^2=a^2+b^2+2ab]

=(10r+8p)^2        

=4(5r+2p)^2

:))

Answer 5

(10r + 8p)(10r + 8p)

2(5r + 4p) times 2(5r + 4p)

4(5r + 4p)(5r + 4p)

Answer 6

100r^2 +160rp + 64p^2

= 4(25r^2 + 40rp + 16p^2)

= 4{(5r)^2 + 2*(5r)*(4p) + (4p)^2}

= 4(5r + 4p)^2

Answer 7

hi kid

(10r+8p)^2

Answer 8

100r^2 + 160rp + 64p^2

4(25r^2 + 40rp + 16p^2)  (taking 4 as common from the given question)

4{(5r)^2 + 2(5r)(4p) + (4p)^2} [with the help of{(a+b)^2 =a^2 + b^2 +2ab}]

4(5r + 4p)^2    

4(5r + 4p)(5r + 4p)

      done done done