Factor this term: 2x^2-2x-3?

Question

in 2 binomials...

Answer 1

2x^2 - 2x - 3

= cannot be factored in two binomials

Answer 2

i dont have a pen and paper with me.. i dont think that its directly factorable.. so you have to use the quadratic formula for this.. let a=2, b=(-2) and c=(-3)...x=(-b±√(b^2-4ac))/2a

Answer 3

2x^2-2x-3 must be factored with the quadratic formula

(This is assuming the expression is equal to zero):

a = 2, b = -2, c = -3

x = [-b± √(b²- 4ac)] / 2a

= [ 2 ± √(4 - (4)(2)(-3)) ] / 4

= [2 ± √(4 + 24)] / 4

= [2 ± √28]/4

= [2 ± 2√7] / 4

= [1 ± √7] / 2

This would make your factors

(x - (1 + √7)/2 )(x - (1 - √7)/2 )

Answer 4

2x^2-2x-3

ax^2+bx+c

a = 2, b = -2, c = -3

x = [-b± √(b²- 4ac)] / 2a

= [ 2 ± √(4 - (4)(2)(-3)) ] / 4

= [2 ± √(4 + 24)] / 4

= [2 ± √28]/4

= [2 ± 2√7] / 4

= [1 ± √7] / 2

This would make your factors

(x - (1 + √7)/2 )(x - (1 - √7)/2 )