Figure of 9 identical rectangles with total area of 72cm sq. Length of each rectangle is 4cm. Find perimeter?

Question

Figure of 9 identical rectangles with total area of 72cm sq. Length of each rectangle is 4cm. Find perimeter?

Answer 1

I'm assuming each rectangle is seperate.

Each rectangle is 8cm sq. (72/9). The area of a rectangle is length x width.

8=l x w

  =4xw

  =4x2.

W=2.

Therefore, the length of a rectangle is 4 cm and the width is 2 cm. The perimeter of 1 rectangle would be 12 cm, so it would be 12x9 or 108cm perimeter in total.

Answer 2

area = length*width

the given length of each rectangle is  = 4 cm

9*length*width=72total area

9*4*width=72

width=72/36=2  

2 cm is the width of each rectangle

perimeter = 2l + 2w = 2(4)+2(2)=12 cm = perimeter of one rectangle

If they stuck all the rectangles together into an odd shape to make a bigger rectangle you will have to use logic to figure out the perimeter of the figure yourself as the perimeter will vary depending on shape. for example if you stuck two next to each other they would have a height of 4 and a width of 4 and a perimeter of 16 cm but if you stacked them they would have a length of 8 and a width of 2 and a perimeter of 20 cm.

Answer 3

total area=72sqcm for 9 rectangles

area of each=72/9=8sqcm

length of each=4cm  and total length=4*9=36cm

width of each=8/4=2cm

perimeter=2*36+2*2=72+4=76cm

Answer 4

The width = (72/9)/4 = 2.

So perimeter of each = 2(4+2) = 12.