Find X (X^2+2ax+3bx = x)?

Question

X^2+2ax+3bx=x

Answer 1

  x^2 + 2ax + 3bx = x

First, rearrange the terms,

  x^2 + 2ax + 3bx -x = 0

  x^2 + (2a+3b-1)x  =  0

Factor out x from the left hand side of the new equation.

  x[x + (2a+3b-1)] = 0

This new equation is true whenever x =0 or x = -(2a+3b-1).

Your solution set is:

    x is an element of { 0, (1 - 2a - 3b) }

Answer 2

to find x in terms of a and b,

x^2 +2ax +3bx =x

x^2 +2ax +3bx -x =0

x^2 + x (2a +3b -1) =0

factor out x

x [ x + (2a +3b -1 )] =0

thus,

x =0 and x +(2a +3b -1 ) =0

x =0 , x = 1 -2a -3b

=)

Answer 3

Solve for x:

x^2+2ax+3bx=x

x^2+2ax+3bx-x=0

x(x+2a+3b-1)=0

x = 0          

x = 1-2a-3b

Answer 4

x²+2ax+3bx = x

x²+2ax+3bx-x = 0

x(x+2a+3b-1) = 0

solution 1, x = 0

solution 2, x+2a+3b-1 = 0

x = 1-2a-3b

.

Answer 5

Please check your 'bracket' in the question again.