Find a positive number that is 2 less than its reciprocal.?

Question

Find a positive number that is 2 less than its reciprocal.

Please explain your process in finding the solution.

Thanks,

Rikou

Answer 1

let x be the number.

x/1  = 1/x + 2/1

You can do the rest.

Answer 2

I'm getting -1 + sqr(2)

Let x : number

x = 1/x - 2

multiply the equation by x

x^2 = 1 - 2x

x^2 + 2x - 1 = 0

Use quadratic formula and only use the plus sign.

Good luck to you !