Question:

Find a1 in a geometric series for which Sn = 300, r = -3, and n = 4 ?

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a 15

b 15/2

c -15

d 1/15

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  1. Sn = a1(r^n - 1) / (r - 1)

    300 = a1((-3)^4 - 1)/(-3 - 1)

    300 = a1(-20)

    -15 = a1

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