Find an equation in slope-intercept form through (2,-5) parallel to y-4=2x?

Question

Find an equation in slope-intercept form through (2,-5) parallel to y-4=2x?

Answer 1

given,

y-4=2x.

the required line is parallel to above equation

so,let the required line be y=2x+c.

this line passes to (2,-5)

-5=2.2+b

b=-9

therefore the required equation is y=2x-9

Answer 2

okay first solve for y.  so y = 2x+4.  so the slope of the line is 2.  now use the point slope formula.  y - y1 = m(x - x1)

y1 = -5

m = 2

x1 = 2

y - (-5) = 2(x - 2)

y + 5 = 2x - 4

y = 2x - 4 - 5

y = 2x - 9

Answer 3

equation  to find the slope intercept form is y-mx+c,m is the slope of the equation c is the constant  

Answer 4

y=2x-9

I am positive this is right

Answer 5

y-4=2x

Solve for y to get into y=mx+b form

y=2x+4

[I just added 4 to both sides]

Parallel lines mean same slope.

the slope in y=2x+4 is 2 and I know this by comparing it to y=mx+b because the m is the slope

the point (2,-5) [(x1,y1)] is used in the eqaution y-y1=m(x-x1)

so plug in the new points and slope for the equaiton and we get..

y-(-5) = 2(x-2)

[next i will distribute the 2....2(x-2)=2x-4]

y-(-5) = 2x-4

[ y-(-5) = y+5]

y+5 = 2x-4

[next I will subtract 5 from both sides]

y = 2x-4-5

y = 2x-9

Answer 6

first you put the equation y-4=2x into slope intersept form (y=mx+b)

                               y-4=2x

                         add 4 to both sides

                               y=2x+4

now you know the line you are looking for has a slope of 2.

your equation so far looks like this y=2x+b so we need to find b

substitute the point (2, -5) into the equation

   it will look like this   -5=2(2)- b

2times 2 is 4

        -5=4-b

4 minus what = -5

  i did -5 minus 4 which is -9

and 4-9=-5 so b is -9

your equation is y=2x-9