Find an equation of the line having the given slope and containing the given point.?

Question

m=2, (6,5)

Answer 1

y = mx + b

5 = 2 x 6 + b

5 = 12 + b

b = -7

Answer 2

The equation for a line is y = mx + b.  The values of these variables are as follows: m = slope, b = y-intercept, and x and y are the point.  You can define any line by providing a slope and a y-intercept (m and b).  In this case, you have a point, (6, 5) and a slope, 2.  m = 2, x = 6, y = 5.  All you have to do is solve for b.  To solve for b, just subtract mx from both sides of the equation.  The answer you're looking for would be "y = 2x + (whatever you determine b to be)".

Answer 3

y-y1=slope*(x-x1)

substitue

y-5=2*(x-6)

y=2x-12+5=2x-7

Answer 4

use the equation y=mx+b and do it yourself. its VERY easy.

hint: if it helps, graph the point and use the slope to draw a line to find the y intercept.

Answer 5

plot your point on a graph, (6,5).  then go up 2 over 1..make another point.  from this last point...go up 2 over 1, so forth and so on.  when you cross the y int.  this will be your "b" in the equation, y=mx+b,

you can also work backwards from (6,5) as long as you follow the slope rule, in this case 2.

m=slope, so you already know y=2x+ ?

Answer 6

Point slope form...

(y - y1) = m (x - x1)

1) y - 5 = 2 (x - 6)

2) y + 4 = 3/4 (x - 6)

Answer 7

hah