Find d/dx for...........?

Question

find d/dx for

y= sqrt( x + sqrt( x+ sqrt( x + sqr(t x+ sqrt (x+..............

Answer 1

how can we answer if half the question isn't even there...

Alright well here's the answer:

the first derivative of y equ...................

Answer 2

y= sqrt( x + sqrt( x+ sqrt( x + sqr(t x+ sqrt (x+..............

so we get

y = sqrt(x+y)

square both sides

y^2 = x + y

diffrentiate to get

2y dy/dx = 1 + dy/dx

dy/dx(2y-1) = 1

dy/dx = 1/(2y-1)

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