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Find dy/dx of ln (e^2x + e^-2x)^1/2?

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  1. Use the chain rule:

    y = ln (e^2x + e^-2x)^½

    = ½ ln (e^2x + e^-2x)

    y ' = ½  (2e^2x - 2e^-2x) / (e^2x + e^-2x)

    = (e^2x - e^-2x) / (e^2x + e^-2x)

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