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Find from first principles the gradient of the tangent to the curve..?

by Guest65054  |  earlier

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y = square root of x

at (4,2)

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  1. y= x^2

    dy/dx= 2x

    dy/dx= 2(4)        (substitute the value of the x co ordinate)

    dy/dx= 8

    therefore the gradient of the tangent to the curve is 8

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