Question:

Find slope of tangent on curve...

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Find the slope of the line to the curve at the point P

Use the formula slope of tangent = lim [x -> c] {f(x) - f(c)} / (x-c)

f(x) = √(x 6), P(3,3)

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  1. Let s = lim [x -> c] {f(x) - f(c)} / (x-c)

    Putting x = c + h:

    s = lim (h -> 0) [ { (c + h + 6)^(1 / 2) - (c + 6)^(1 / 2) } / h ]

    Multiplying and dividing (c + h + 6)^(1 / 2) - (c + 6)^(1 / 2) by (c + h +  6)^(1 / 2) + (c + 6)^(1 / 2) gives:

    [ (c + h + 6) - (c + 6) ] / [ (c + h +  6)^(1 / 2) + (c + 6)^(1 / 2) ]

    = h / [ (c + h +  6)^(1 / 2) + (c + 6)^(1 / 2) ]

    Therefore:

    s = lim (h -> 0) ( h / { h [ (c + h +  6)^(1 / 2) + (c + 6)^(1 / 2) ] } )

    = lim (h -> 0) ( 1 / [ (c + h +  6)^(1 / 2) + (c + 6)^(1 / 2) ] )

    = 1 / [ (c + 6)^(1 / 2) + (c + 6)^(1 / 2) ]

    = 1 / { 2(c + 6)^(1 / 2) }

    Putting c = 3 gives:

    1 / { 2 sqrt(9) }

    = 1 / 6.

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