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Question

Water drips from the nozzle of a shower onto the floor 240 cm below. The drops fall at regular (equal) intervals of time, the first drop striking the floor at the instant the fourth drop begins to fall. Find the locations (above the floor in cm) of the second and third drops when the first strikes the floor. Second drop?

Third drop?

Answer 1

objects get faster as they fall (neglecting friction); the distance an object falls in a time t is:

d=1/2 gt^2

where d is distance, g is accel due to gravity (9.8m/s/s) and t is time

we can find the time it takes for the first drop to hit the floor:

t=sqrt[2d/g]=0.7s

if the first drop left the nozzle at t=0, the second drop left at t=0.233s and the third drop left at t=0.466 s

therefore, the second drop has been in the air for 0.466s and has fallen a distance&quot;

d=1/2(9.8)(0.466)^2=1.06 m (106 cm)

the third drop has been in the air for 0.233s and has fallen 0.266 m or 26.7cm

Answer 2

80 cm and 160 cm