Find the 1st derivative?

Question

y = √2x^2 - 8x +4

Could some kind person tell me how to find the 1st derivative of that? I will be very grateful :]

Answer 1

Find the derivative of each term, add them together, and simplify

Note that the following assumes that the square root symbol you have applies only to the first term

y = (2 * x^2)^(1/2) - 8*x + 4

y' = (1/2) * (2 * x^2)^(-1/2) * (2 * 2 * x) - 8

y' = 4x / (2 * (2 * x^2)) - 8

y' = 4x / (2x * sqrt(2)) - 8

y' = 2/sqrt(2) - 8

y' = sqrt(2) - 8

Answer 2

Sure; using √2 as the coefficient of x², we can differentiate it as a

quadratic function, which yields: dy/dx = 2√2x - 8

Hope this helps