Find the center and radius of x^2+y^2=36?

Question

Find the center and radius of x^2+y^2=36?

Answer 1

the given equation can be re-written as:

(x - 0)^2 + (y - 0)^2 = 6^2

Therefore, the center is (0, 0) and r = 6

Good Luck!

Answer 2

the equation for a circle is (x-a)^2+(y-b)^2=r^2

since there's no a or b in your equation the center of the circle is in (0,0)

and the radius is found by solving the equation:

r^2=36 => r=6

Answer 3

Centre the origin

r = 6

Answer 4

It's a circle of radius 6 and centered at the origin (0,0).

Answer 5

Center = (0,0)

Radius = 6     (Sqrt of 36)