Question:

Find the co-ordinates that this equation crosses the x-axis at?

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y-(x-1)^3 - 4(x-1)

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  1. y-(x-1)^3-4(x-1)=0

    at x axis y=0

    0-(x-1)^3-4(x-1)=0

    (x-1)((x-1)^2-4)=0

    (x-1)(x^2-2x+1-4)=0

    (x-1)(x-3)(x+1)=0

    x=1...y=0

    x=3...y=16...not correct

    x=-1...y=-16....not correct

    so the coordinates are (1,0)

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