Find the distance between the points (2, -5) and (-3, 0)....Theres more/ please HELP!?

Question

Find the distance between the points (2, -5) and (-3, 0). (don't forget to simplify)

2.Find the midpoint of the points (2,-5) and (-3, 0).

3.Which postulate relates to the following scenario?

A wedding videographer uses a tripod to hold the video camera.

a.)Through any two points, there is exactly one line.

b.)A line contains at least two distinct points.

c.)Through any three noncollinear points, there is exactly one plane.

d.)A plane contains at least three noncollinear points.

Answer 1

The distance formula is: d= sqr root of ((y2-y1)^2+(x2-x1)^2)

so d= sqr rt: (0+5) + (-3-2) ...d= sqr rt: 25+25...d=sqr root 50 = 7.07

midpoint: find average of y's and then find average of x's: (0+-5)/2 = -2.5

-2.5 = y-coordinate.

(2-3)/2 = -.5

-.5 = x-coordinate

midpoint: (-0.5, -2.5)