Find the distance????????????????

Question

Find the distance from the point (-5, 2, -3) to the

(a.) xy-plane

(b.) xz-plane

(c.) yz-plane

(d.) x-axis

(e.) y-axis

(f.) z-axis

Answer 1

distance of point (--5, 2, --3) from

(a.) xy-plane is 3 below it or --3

(b.) xz-plane is 2 above it

(c.) yz-plane is 5 on left or --5

(d.) x-axis is sqrt(2^2+3^2) = sqrt(13)

(e.) y-axis is sqrt(5^2+3^2) = sqrt(34)

(f.) z-axis is sqrt(5^2+2^2) = sqrt(29)

Answer 2

a) xy [ z=0] ... 3

b) xz [y=0] ....2

c) yz [x=0] ...5

d) x axis ............root(13) .....[ 2^2 + -3^3}^1/2

e) y axis ............root(34) .....[-5^2 + -3^2]^1/2

f) z axis..............root(29)......[-5^2 + 2^2]^1/2