Find the equation in slope-intercept form of the line that passes through the points (-3, 1) and (-2, -5).?

Question

Find the equation in slope-intercept form of the line that passes through the points (-3, 1) and (-2, -5).?

Answer 1

y2 - y1 /x2 - x1

-5--3/-2-1

-5+3/-3

-2/-3

=2/3

Answer 2

use the equation

m=(Y2-Y1)/(X2-X1)

to find the slope

m= (-5-1)/(-2- -3) which equals -6/1  

slope= -6

your equation looks like this so far y= -6x+b

we need to find b

so pick one of your points and plug it in to the equation

i picked (-3,1)

(1)= -6(-3)- b

-6 times -3 equals 18

so 18 minus what equals 1?

17

so your equation is y= -6x-17

to check your work you can plug the other point into the equation and see if it also works out if both points do not work out your equation is wrong.

hope i helped. :)

Answer 3

m = (y2 - y1)/(x2 - x1)

b = y1 - m*x1 = y2 - m*x2

I assume you own a calculator.

Answer 4

umm 6/-1 i think

y2-y1/x2-x1...