Find the equation of a line that's perpendicular to y=-5/6+7, and going in through the point (5,15)?

Question

Could someone please show me how to do this I am so confused!

Answer 1

First find the perpendicular lines slope, which is the negative recipricol of the original line... since the original line's slope is -5/6 in this case it will be 6/5.  Now you have y=(6/5)x+b so plug 5 and 15 in for x and y and you can find b... 15=(6/5)5+b or just 15=6+b so be must be 9.  Now you have your total equation y=(6/5)x+9

Answer 2

A perpendicular line has a negative reciprical slope of the origional line.

slope = 6/5

y- 15 = 6/5(x-5)

y = 6/5x +9

Answer 3

oh yah this one got me too!!  don't worry though, i told tracy to lay off for the time being.  good luck jake!!!  you're doing great.

Answer 4

maby yu want y=-(5/6)x+7?

in that kase, slope=-5/6, so need +- 90 degrees from that

  

Answer 5

Perpendicular slope = negative reciprocal = +6/5

y = mx+b

15 = (6/5)(5) + b

15 = 6 + b

b = 9

y = (6/5) x + 9