Find the equation of a straight line?

Question

Find the equation of the straight line which is parallel to the line with equation 2x + 3y = 5 and which passes through the point (2, - 1)

Answer 1

3y=-2x+5

y=-2/3x+5/3

slope=-2/3

parallel line have same same slope.

y=mx+c

-1=(-2/3)(2)+c

c=1/3

equation for straight line is

y=(-2/3)x+1/3

3y=-2x+1

2x+3y=1

Answer 2

solve for y. the slope is the number that is multiplied by x.

then look at the equation y=mx+b.

plug in y=-1 and x=2

-1=(slope from first equation)x +b

solve for b

the answer you will get will be in the form

y=(slope)x + (the b you just solved for)