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Find the equation of the plane through (1,-1,3) parallel to the plane 3x+y+z=7?

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Find the equation of the plane through (1,-1,3) parallel to the plane 3x+y+z=7?

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  1. The product of normal direction and any line on the plane is zero. So, the equation can be written as,

    3(x-1)+(y+1)+(z-3) = 0

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