Question:

Find the first four values of the recursive function?

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f(1)=3; f(n)=f(n-1)+2n

please explain how!!!

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  1. f(2)=f(2-1)+2(2)=f(1)+4=3+4=7

    f(3)=f(2)+2(3)=7+6=13

    f(4)=f(3)+2(4)=13+8=21

    f(5)=f(4)+2(5)=21+10=31

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