Find the force exerted by the gas on one of the walls of the container.?

Question

A sealed cubical container 26.0 cm on a side contains three times Avogadro's number of molecules at a temperature of 19.0°C.

Answer 1

Ideal gas law:

PV = nRT

pressure x volume = number of moles x ideal gas constant [8.314472(15) J · K-1 · mol-1 ] x temperature [in kelvin. to get celcius to kelvin, take C + 273.15 = K.]

in your question, you have the volume [26^3], you have the number of moles [3mol], you have the temperature. so you can find the pressure.

P = (nRT)/V

pressure = force / area.

the gas exerts force on 6[26^2]cm^2, since that is the area of the six inner surfaces of the cube.

there you have it!

cheers :D