Question:

Find the half life of a radioactive substance that decays by 10% in 10 years.?

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I need some help with starting off this question. Please help me figure out this problem! :]

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  1. well u need to calculate in how many years the half of radioactive substance decays....

    0.9^x = 0.5

    x = log 0.5 / log 0.9

    x = 6.58

    6.58 * 10y = 65.8y


  2. cessium??

  3. I like to make up a number for the amount of atoms we start with say 1000 atoms.

    y = 1000 atoms [e^(t)(k)]   k is just a constant that determines how fast it will decay

    we also know

    900 = 1000 [e^ 10(k)]   because it loses 100 atoms when t = 10

    to solve for k apply a rule of natural log aka (ln).  Just bring down the exponents.

    0.9 = e^ (10k)

    ln(0.9) = 10k

    k = -.010536

    now that you have k, find the time that we have 500 atoms left

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