Question:

Find the least common multiple of the given terms?

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p^2-7p-30 & p^2+6p+9

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  1. It is too complicated of a problem to do by simply staring at it.  The first thing you need to do is factor each separate equation.

    Use quadratic equation to find

    p^2 - 7p - 30 = (p-10)(p+3)

    Use quadratic equation to find

    p^2 + 6p + 9 = (p + 3)(p+3)

    Notice that each equation has a p+3 in it, so the least common (and only common) multiple is (p + 3)


  2. To find the answer:

    1) Simplify and solve each parenthetical:

    p^2-7p-30 = (p-10)(p+3), so p=10 or -3

    p^2+6p+9 = (p+3)(p+3), so p= -3

    2) The least common multiple is the lowest number that can solve both equations.  In this case, the answer is -3.

  3. do not confuse  the highest common factor  with the smallest multiple!!!

    the right answer is:  (p-10)(p+7)(p+3)

  4. (p + 3)²(p - 10)

  5. (p-10)(p+7)(p+3)

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