Find the number: Need help with my fourth grader's Challenge Math Homework assignment. I can not get it.?

Question

Please I need help with my fourth grader's challenge Math homework:

Find the number.

It has only two different digits, but they repeat.

The digits appear in the same order in both periods.

The sum of the digits is 20 and the ones digit is five more than the tens digit.

What is the number?

( I was able to help her with all of the questions except this one. please help also need explanation so I can try to explain to her)

Answer 1

  I hope I did this right, but the length of the number I came up with is 5,

however, there are only 2 different digits: 33338.

I don't know what you mean "both periods", but when you add these numbers together, it equals 20:

  3 + 3 +3+ 3=12

  12+ 8 = 20

The ones digit is the 8, which is 5 more than the tens digit (the last 3).

This is like numerology, where you add the digits together of a longer number down until you have a single number. People use it to figure out their lucky number , for instance, by using their birth date. For someone who was born August 13, 1989, you would add 8 (for the 8th month) + 1+3+1+9+8+9=39, then 3+9=12, and finally 1+2=3. This means that person's lucky number is 3.

Answer 2

Whoa, this is ridiculously difficult for fourth grade.  I took math through college, including calculus, and I am struggling with this one.  

Let's look at this:

"Find the number."  One single number, no indication as to how many digits.

"It has only two different digits, but they repeat."  Two different numerals that repeat in the number.  Such as 22223333, just 2's and 3's repeating.

"The digits appear in the same order in both periods."  So, I guess that means we're looking for something more like 2323, or 23322332, as long as it repeats in two different segments.

"The sum of the digits is 20."  All of the digits have to add up to 20.

"The ones digit if five more than the tens digits."  That would be something like 1616, where 6 is five more than 1, except that doesn't total 20.  

So, here are some possibilities:

50055005 (probably the best answer)

5000550005 (also meets the requirements, you could extend the 0's infinitely)

5050505.0 (a stretch, I know)

1111611116 (another possibility)

111611116.1 or 11611116.11 or 1611116.111 or 611116.1111 (only if you're irritated at the teacher for assigning this in the first place)

Answer 3

I have no idea! This is for fourth grade!

Urrm..., no I srsly don't know! Good luck!

Answer 4

15+5

Answer 5

This is a really challenging question.

Here are all of the two digit numbers that add up to 20:

0 + 20

1 + 19

2 + 18

3 + 17

4 + 16

5 + 15

6 + 14

7 + 13

8 + 12

9 + 11

10 + 10

now 1 and 0 repeat in 10 + 10 but neither is five more than the other.  however  6 + 14 do but those are three different digits, not two.  I would have your daugther come up with the same list I did and talk the problem out with her, see what she comes up with.

Hope this helps!  Good luck!