Find the potential difference at each point from a to d?

Question

the pictures looks like this-> battery under a is 15 V and under b is 9V

a------/\/\/\/-------b

| 4 ohms |

| |

-------- ----------

--- ----

-------- ----------

--- ----

| |

| |

d-------/\/\/\/-------c

2 ohms

this is suppose to look like a closed circuit with a to d at the four corners, two batteries on the vertical sides and 2 resistors on the horizontal sides

there is also a grounding symbol below c

Answer 1

Really can't decode your drawing. But calculate total current first. Voltage is either 15+9 or 15-9 depending on circuit. I = V/6, so total current is either 14/6 or 6/6 amps. Call it 1 amp for now.

Calculate voltage drops across each resistor, call those V4 and V2.

Then just start at ground and move, say, clockwise around the loop, adding batteries that are -+ in the CW direction or subtracting if they are +-. Batteries are treated as negative

So, starting at c, at d you have + 2 volts. At a you have (+2 - 15) volts if I got the polarity right. At b you have (+2 - 15) + 4 volts.

http://en.wikipedia.org/wiki/Kirchhoff%2...