Find the slope of a line perpendicular to ?

Question

3x+10y=-20

Answer 1

First, find the slope of this original line by solving for y.

3x + 10y = -20

10y = 3x - 20

y = (3/10)x - 2

Since y = mx + b where m is the slope and b is the y-intercept, the slope is (3/10).

Perpendicular lines have a slope that is the negative inverse of the original line.

perpendicular line's slope = -1 / slope of original line = -1 / (3/ 10) = (-10/3)

The slope of the perpendicular line is (-10/3)

Answer 2

put it into slope intercept form...

so

10y=3x-20

y=3/10-20

and then you find the negative recipricole for the slope of a perpindicular line... so

y=-10/3-20

(Flip the slope of the regualr line and make it the opposite, so if it's positive make it negative and if it's negative make it positive.)

Answer 3

First, you need to solve for y to change your line to slope-intercept form, so that you know th slope of your line.

Slope-intercept form of line: y= -3/10x-2

Perpendicular lines always have opposite and inverse slopes, so the slope of your line is: 10/3

Answer 4

For perpendicular lines, the slope of the line x the perpendicular line = -1.

Put this line in slope intercept form:

10y = -3x - 20

y = -3x/10 - 2

So, the slope for this is -3/10

-3/10 x m = -1

m = 10/3

Therefore, the slope of the perpendicular line is 10/3.