Question:

Find the solutions to: | x squared + 1 | = 5?

by  |  earlier

0 LIKES UnLike

Find the solutions to: | x squared + 1 | = 5?

 Tags:

   Report

13 ANSWERS


  1. 2, -2, square root of 6 times i, negative square root of 6 times i


  2. |x^2 + 1|= x^2+1  

    thus,

         x^2+1 = 5

    or, x^2 = 4

    or, x = 2    

                    that's it.

  3. X2 + 1 = 5

    X2=4

    X=+or-2

    -X2-1 = 5

    X2 = -6

    X= + or - square root of 6

  4. | x squared + 1 | = 5

    x^2 + 1 = + 5 and - 5

    x^2 = -1 + 5  and -1 + -5

    x^2 = -6, 4

    x = -6 (no real sol'n)   ,  x = √4

    x= 2

    SS = {, 2}

  5. x² + 1 = 5

    x² = 4

    x = ± 2

    x² + 1 = - 5

    x² = - 6

    x = 6 i²

    x = ± √6 i

  6. 2 is the answer

  7. |xˆ2 + 1| = 5

    This has two solutions because it is an absolute value.

    Solution #1:

    xˆ2 + 1 = 5

    xˆ2 = 5 - 1

    xˆ2 = 4

    √(xˆ2) = √(4)

    x = 2 (<==ANSWER #1)

    Solution #2:

    xˆ2 + 1 = -5

    xˆ2 = -5 - 1

    xˆ2 = -6

    √(xˆ2) = √(-6)

    x = -√6 (<==ANSWER #2)

    Hope I helped!

  8. the answer is not just '2'.  the answer is x=2 OR -2

    the ||s mean 'absolute value', so you must consider negatives.

    2x2+1=5 AND -2x-2=5

  9. 2

  10. x = 2 or -2

  11. x is 2

  12. the modulus signs means all the solutions to:

    x^2 + 1 = 5

    OR

    - (x^2 + 1) = 5

    so the solution set is all the solutions to the first equation, and all the solutions to the second equation.

    The solutions to the first equation:

    x^2 + 1 = 5

    x^2 = 4

    x = +- 2

    The solutions to the second equation:

    - (x^2 + 1) = 5

    x^2 + 1 = -5

    x^2 = -6

    There are no solutions to this equation since no real number squared can result in a negative number.

    So the solution set is:

    {-2, 2}

    -√6 is not a solution for this is because √-6 does NOT equal -√6.  ÃƒÂ¢Ã‚ˆÂš-6 is an imaginary number and i dont think u are expected to include this in your solution set.



  13.   There are three solutions and they are 2, -2 and i*sqrt(6).  

    As x squared + 1  is within abs the sign can be negative or positive. If

    x squared + 1 is positive, then it is = 5.  So,

    x squared = 5-1 = 4. So

    x = plus or minus root 4

    So x = -2 or 2.

    If x squared +1 is negative, then it is = -5. So

    x squared = -5 -1 = -6. So

    x = sqrt(6)*sqrt(-1).

    => i*sqrt(6).

    S.S  =  {-2, 2, i*sqrt(6)}

    I hope this is clear.  

Question Stats

Latest activity: earlier.
This question has 13 answers.

BECOME A GUIDE

Share your knowledge and help people by answering questions.