Find the speed of train A and train B?

Question

Speed of train A is 10 mph slower than the speed of train B. Train A travels 220 miles in the same time it takes train B to travel 270 miles. Find the speed of each train?

Answer 1

1. Sa = Sb - 10

2. 220/Sa = 270/Sb

now solve:

220Sb = 270Sa

220Sb = 270 * (Sb - 10)

220Sb = 270Sb - 2700

50Sb = 2700

Sb = 2700/50 = 54 miles per hour.

Sa = 54-10 = 44 miles per hour

Answer 2

This is a mathematics "word" problem, and it belongs in the "HOMEWORK HELP" section. Just because it contains the word "train" does not make it a question for the "Rail" sub-section.

Answer 3

v=s/t

t=s/v

vA=vB-10

sA=220

sB=270

tA=tB

220 / (vB-10) = 270 / vB

220 vB = 270(vB-10)

vB=54

vA=44

Answer 4

A=speed of train A

B=speed of train B

1) A=B-10

2) 220A=270B

    22A=27B

     A=27/22B

2 in 1

27/22B=B-10

10=B-27/22B

10=B(1-27/22)

B=10/(1-27/22)

B=-9.773

A=-9.773  -10

A=.277

A=

Answer 5

wow

that is awfully complicated

luckily I am the engineer on the slow train and dont have to do complicated math

Answer 6

try the math or homework categories....