Find the tension in the supporting cable while the elevator is being brought to rest.?

Question

elevator and its load have a total mass of 800kg. elevator moving downward at 10.0 m/s^, it is brought to rest with constant acceleration in a distance of 25.0 m.

Answer 1

Hint:

Use the equations of motion to determine the acceleration.

v1=-10m/s

v2=0

s1=25m

s2=0

t1=0

t2=?

Sum of forces in y = ma

T-W=ma